find all values of x for which distance between points p (2,-3) and q (x,5) is 10 units.
Answers
Answered by
1
Answer:
Step-by-step explanation:
Let p and q equidistant to each other then by distance formula as we have pq=10 units so, pq=√(x1-x2)+(y1-y2) 10=√(x-2)²+(5+3)² 100=x²-4x+4+64. 100-68=x²-4x. 32=x²-4x. X²-4x-32. X²-8x+4x-32. x(x-8)+4(x-8) (x+4)(x-8) therefore X=-4 or x=8
yashwant74:
Pls mark me as branlist
how
you formula is wrong. answer is correct
Hey friend formula is wright √(x1-x2)² + (y1-y2)²
no
Ya a
in place of x1-x2 and y1-y2 there will be x2-x1and y2-y1
Similar questions