Math, asked by harshit2222, 9 months ago

find all values of x in -pie, pie satisfying the equation 8 to the power of 1+cosx+cos square x+....=4 cube​

Answers

Answered by amitnrw
6

Answer:

-π/3  & π/3

Step-by-step explanation:

Find all values of x in -pie, pie satisfying the equation 8 to the power of 1+cosx+cos square x+....=4 cube​

Let say  n = 1 + Cosx + Cos²x + .....................

Then 8ⁿ  = 4³

=> 8ⁿ = 64

=> 8ⁿ = 8²

=> n = 2

1 + Cosx + Cos²x + .....................     = 2

Sum of infinite gP  = a/(1 - r)    

1/(1 - Cosx) = 2

=> 1 - Cosx = 1/2

=> Cosx = 1/2

x =  ±π/3

x = 2kπ ±π/3

Values between - π & π

= (-π/3  & π/3)

Answered by vijayababu3399
1

Answer:

Step-by-step explanation:

Find all values of x in -pie, pie satisfying the equation 8 to the power of 1+cosx+cos square x+....=4 cube​

Let say  n = 1 + Cosx + Cos²x +  

Then 8ⁿ  = 4³

=> 8ⁿ = 64

=> 8ⁿ = 8²

=> n = 2

1 + Cosx + Cos²x +     = 2

Sum of infinite gP  = a/(1 - r)    

1/(1 - Cosx) = 2

=> 1 - Cosx = 1/2

=> Cosx = 1/2

x =  ±π/3

x = 2kπ ±π/3

Values between - π & π

= (-π/3  & π/3)

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