Question

Find all valug sin univers 2 +I(0)
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Answer 1

Answer:

Solution

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Correct option is D)

⇒

1−2isinθ

2+3isinθ

Purely imaginary means real part =0

1−2isinθ

2+3isinθ

×

1+2isinθ

1+2isinθ

=

1−(2isinθ)

2

2+4isinθ+3isinθ−6sin

2

θ

=

1+4sin

2

θ

2+7isinθ−6sin

2

θ

Real part is =

1+4sin

2

θ

2−6sin

2

θ

This is equal to zero.

⇒

1+4sin

2

θ

2−6sin

2

θ

=0

So, 2=6sin

2

θ

sin

2

θ=

3

1

sinθ=±

3

1

∴ θ=sin

−1

(

3

1

)