Question

Find all zeroes 5x^2 + 12x+7 by spliting the middle term

Answer 1

$\huge \red{ \boxed{ \bf{ \ulcorner{ \mid{ \overline{ \underline{ANSWER}}}}}\mid }}$

$\huge \pink{ \mid{ \overline{ \underline{ \mathbb{GI} \mathit{V}\mathfrak{EN}}}} \mid}$

The solution is as follows

$=>5 {x}^{2} + 12x + 7 \\ = > 5 {x}^{2} + 5x + 7x + 7 \\ = > 5x(x + 1) + 7(x + 1) \\ = > (5x + 7)(x + 1) \\ = > so \\ = > x = - \frac{7}{5} \: and \: - 1$

❤Thanks For Asking $\underline\bold{ANMOL }$

✶⊶⊷⊶⊷⊷⊶⊷ ❍⊷⊶⊷⊶⊷⊶⊷✶

$\mathcal{\red{\huge {Hope\:it\:helps}}}$