Find all zeroes of f(x)=x3-2x
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12
Answer:
Step-by-step explanation:
x³-2x=0
x(x²-2)=0
x(x-√2)(x+√2)=0
So, the roots are -√2,√2,0.
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Hey there⏩⏩⏩
given== f(x)===
x^3 - 2x = x(x^2-2)= 0
x =0
x^2-2 =0
x^2= 2
x =√2
given== f(x)===
x^3 - 2x = x(x^2-2)= 0
x =0
x^2-2 =0
x^2= 2
x =√2
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