Find all zeroes of polynomial 2x (cube) x (sq)-6x-3 if two of its zeroes are -(root)3 and (root)3
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Let f(x) = 2x3+x2-6x-3
Given: (x+√3)(x-√3) are the zeros of f(x).
product of zeros = (x+√3)(x-√3) =x2-3
therefore, on dividing the f(x) with x2-3 , we get, 2x+1
now,
2x+1=0
2x= - 1
x=(-1/2)
hence, the other zeros are (-1/2)
Given: (x+√3)(x-√3) are the zeros of f(x).
product of zeros = (x+√3)(x-√3) =x2-3
therefore, on dividing the f(x) with x2-3 , we get, 2x+1
now,
2x+1=0
2x= - 1
x=(-1/2)
hence, the other zeros are (-1/2)
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