Find all zeroes of the polynomial 2x4-9x3+x2+3x-1 if two zeroes 2+√3)(2-√3)
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ZERO'S ARE :-(2+√3)(2-√3) ==> 4-3 ==> 1
1 = X
0 = X- 1
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Answer:
All zeroes of p ( x ) are 1 , - 1 / 2 , 2 + √ 3 and 2 - √ 3
Step-by-step explanation:
Given :
p ( x ) = 2 x⁴ - 9 x³ + 5 x² + 3 x - 1
Two zeroes of p ( x ) :
2 + √ 3 and 2 - √ 3
p ( x ) = ( x - 2 - √ 3 ) ( x - 2 + √ 3 ) × g ( x )
g ( x ) = p ( x ) ÷ ( x² - 4 x + 1 )
On dividing ( 2 x⁴ - 9 x³ + 5 x² + 3 x - 1 ) by ( x² - 4 x + 1 )
We got ,
g ( x ) = 2 x² - x - 1
By splitting mid term
2 x² - 2 x + x - 1
2 x ( x - 1 ) + ( x - 1 )
( x - 1 ) ( 2 x + 1 )
Now zeroes of g ( x )
x = 1 or x = - 1 / 2 .
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