Question

Find all zeroes of the polynomial 4 − 3 3 − 5 2 + 21 − 14, if two zeroes are 7 and − 7.​

Answer 1

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x^2 -7 is a factor of our polynomial, so

Let the polynomial be

(x^2-7) ( x^2 +ax+2)

= x^4 + ax^3–5x^2 -7ax —14

Clearly, a = -3

So, x^2 -3x +2 = 0, which means x = 1, 2

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Answer 2

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x^2 -7 is a factor of our polynomial, so

Let the polynomial be

(x^2-7) ( x^2 +ax+2)

= x^4 + ax^3–5x^2 -7ax —14

Clearly, a = -3

So, x^2 -3x +2 = 0, which means x = 1, 2

${\small{{\tt{\color {red}{A᭄nswer by BSR࿐}}}}}$