find all zeroes r(x)=x^3+x^2+4x+12 if one zero is x+-2
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You should not write one zero is x+-2
You should write one zero is +2 or -2.
In this case one zero is -2. +2 is not possible because if you put x=+2 in that polynomial you will not get zero.
Now if one zero is -2, then factor is (x--2)= x+2
Now divide the polynomial by x+2, you will get
x^2-x-6
Now factorise this by mid term splitting
=(x-3)(x+2)
So other two zeroes are +3 and -2
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