Question

Find all zeroes2x4+7x3-19x2-14x+30 if two of iys zeroes are under root2 and -underroot2

Answer 1

Answer:

Step-by-step explanation:hope this will help you

Answer 2

♓♒♈ ♍⛎✝♒ ✋✋

$\huge\mathfrak{here's \: ur\: answer}$

Given,

$p(x) = {2x}^{4} + {7x}^{3} - 19 {x}^{2} - 14x + 30 \\ \\ two \: zeroes = \sqrt{2} \: and - \sqrt{2}$

Here,

$\sqrt{2}$ and- $\sqrt{2}$ are the two zeroes of p(x)

=> x = $\sqrt{2}$ and x =-$\sqrt{2}$ are the zeroes of p(x)

=> => x - $\sqrt{2}$ =0 and x +$\sqrt{2}$=0 are the zeroes of p(x)

=> $(x - \sqrt{2} )(x + \sqrt{2})$ is the factor of p(x)

=> ${x}^{2} - {( { \sqrt{2} })}^{2}$ is the factor of p(x)

=> ${x}^{2} - 2$ is the factor of p(x)

$\bold {follow \: 1st \: attachment}$

Other factor => 2x^2 + 7x - 15 = 0
=> 2x^2 + (10-3)x - 15 = 0
=> 2x^2 + 10x - 3x - 15 = 0
=>2x ( x + 5) - 3 (x +5) = 0
=>(x + 5)(2x - 3) = 0

therefore x = -5
and
x = $\frac{3}{2}$

$\huge \boxed{Answer = \: - 5 \: and \: \frac{3}{2} }$

✌✌hope it helps u ✌✌

with regards @creamiepie ❤❤