Question

Find all zeros for the function: g(x)= 2x^2+7x-4. Fully simplify all answers, including non-real zeros.

Answer 1

Answer:

Step-by-step explanation:

2x^2 + 7x - 4 = 2x^2 - x + 8x - 4

= x(2x - 1) + 4(2x - 1)

= (2x - 1)(x + 4)

the zeroes of g(x) are 1 / 2 and - 4.

Answer 2

${2x}^{2} + 7x - 4 \\ \\ = {2x}^{2} + 8x - x - 4 \\ = 2x(x + 4) - 1(x + 4) \\ = ( 2x - 1)( x+ 4) \\ 2x - 1 = 0 \\ 2x = 1 \\ x =0.5 \\ x + 4 = 0 \\ x = - 4 \\ \\ these are the \: zeroes \: of \: polynomial \: 2 {x}^{2} + 7x - 4$

2x-1=0

2x=1

x=1/2

x+4=0

x=-4

1/2 and -4 are the zeroes polynomials 2x^2+7x-4

hope it helps

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