Question

find all zeros of 2x⁴ - 3x³-3x²+6x -2
two zeros are √2,-√2​

Answer 1

Answer:

1/2,1

Step-by-step explanation:

given two zeros are √2,-√2

so x-√2,x+√2 are the factors of the polynomial

multiply both the factors

we get  (x-√2)×(x+√2)=x²-2

divide the polynomial with x²-2

x²-2) 2x⁴ - 3x³-3x²+6x -2(2x²-3x+1

        2x⁴         -4x²

               -3x³ + x² +6x                zeros of 2x²-3x+1 are 1,1/2

               -3x³        +6x

                         x²       -2

                        x²       -2

                                0