Find all zeros of quadratic polynomial 2x4 -10x3 +5x2+15x -12, if two of its zeros are 2 3 & - 2 3 .
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To get the zeros of 2x4 -10x3 +5x2+15x -12, we equate it to zero then solve for x
2x4 -10x3 +5x2+15x -12x = 0
(x-1)(x-4)(√2x+√3)(√2x-√3) = 0
(x-1) = 0 ⇒ x = 1
(x-4) = 0 ⇒ x = 4
(√2x+√3) = 0 ⇒ x = -√(3/2)
(√2x-√3) = 0 ⇒ x = √(3/2)
The roots are:
1, 4, -√(3/2) and √(3/2)
2x4 -10x3 +5x2+15x -12x = 0
(x-1)(x-4)(√2x+√3)(√2x-√3) = 0
(x-1) = 0 ⇒ x = 1
(x-4) = 0 ⇒ x = 4
(√2x+√3) = 0 ⇒ x = -√(3/2)
(√2x-√3) = 0 ⇒ x = √(3/2)
The roots are:
1, 4, -√(3/2) and √(3/2)
Answered by
5
Hey! ! !
Solution :-
☆ factor of 2x4 + x3 -14x2 + 5x+ 6, then we apply division algorithm,
☆ See the attached pic
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
Solution :-
☆ factor of 2x4 + x3 -14x2 + 5x+ 6, then we apply division algorithm,
☆ See the attached pic
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
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