Question

Find all zeros of the polynomial x⁴ + x³ - 9 x² - 3x + 18.​

Answer 1

Answer:

$\mathrm{Factor\:x^4+x^3-9x^2-3x+18:\quad \left(x-2\right)\left(x+3\right)\left(x^2-3\right)}$

Step-by-step explanation:

$x^4+x^3-9x^2-3x+18$

$=\left(x-2\right)\frac{x^4+x^3-9x^2-3x+18}{x-2}$

$=\left(x-2\right)\left(x^3+3x^2-3x-9\right)$

$=\left(x-2\right)\left(x+3\right)\left(x^2-3\right)$