Question

Find all zeros of x4-6x3-26x2+128x-35 are 2+√3 and 2-√3 two zeros are given

Answer 1

Answer:

x^2-4x+1

Step-by-step explanation:

Let the alpha = 2+√3

bita = 2-√3

product= alpha×bita

2+√3×2+√3

2^2 - √3^2

4-3

1

sum= alpha + bita

2+√3 + 2-√3

2+2

4

Quadratic equation x^2 - (alpha + beta)

-x+ alpha beta

x^2 -4x + 1

Hope it's help uh

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