Question

find alpha and beeta if sin(alpha+2 beeta)=root3/2 and cos(alpha+4beeta)=0

Answer 1

Step-by-step explanation:

sin(α+β)=1,sin(α−β)=1/2

⇒α+β=π/2,α−β=π/6

⇒α=3π,β=6π

=tan(α+2β)tan(2α+β)

=tan(32π)tan(65π)

=(−3)(−1/3)=1 

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