Question

find alpha + beta and alpha×beta when p(x)=x(x^2+1)

Answer 1

hey mate here is your answer:-

p(x)=x³+x

and it can also be x³+x+0

so, sum-

$\alpha + \beta = - \frac{b}{a}$

so,

$\alpha + \beta = - 1$

and,

$\alpha \beta = \frac{c}{a} = \frac{0}{1} = 1$

hope it helps u.

please mArK it as BrAiNlIsT.....