find alpha+betha and alpha ×beta
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first we need to know value of alpha + beta and alpha × beta :-
Let's consider the equation = ax^2 + bx + c = 0
From the given equation in question i.e 5x^2 +6X+1=0
a=5, b=6,c=1
Using the quadratic formula,
Alpha + Beta = -b/a
Now, putting the value
=> Alpha + Beta = -6/5
Alpha * Beta = c/a
=> Alpha * Beta = 1/5
now, How do you find alpha and beta :-
- If the quadratic equation ax2+bx+c=0 , has roots αandβ, then α+β=−baandα⋅β=ca. Here,
- x2−22x+105=0⇒a=1,b=−22,c=105.
- So, α+β=−−221=22,andαβ=1051=105. Now, (α−β)=√(α+β)2−4αβ ,... where,(α>β)
- (α−β)=√(22)2−4(105)
- (α−β)=√484−420=√64=8.
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