Question

find alpha square plus bita square if px is equal to x2-px+q

Answer 1

HOPE IT HELPS...........

Answer 2

$px = {x}^{2} - px + q \\ {x}^{2} - 2px + q = 0 \\ a = 1 \\ b = 2p\\ c = q \\ \alpha + \beta =- 2p ........eq(1) \\ \alpha \beta =q.......eq(2)$
Now according to the question we have to find
${ \alpha }^{2} + { \beta }^{2}$
$= > { (\alpha + \beta )}^{2} - 2 \alpha \beta \\ = > from \: eq \: 1 \: and \: 2 \\ = > {( - 2p)}^{2} - 2q \\ = > 4 {p}^{2} - 2q \\ = > 2(2 {p}^{2} - q)$
Here is your answer....