Question

find altitude of a equilateral triangle whose side is 8 cm
please answer​

Answer 1

Answer:

by pytha goras theorom

ans is

$4 \sqrt{3} \: \: \: ans$

mark brainliest

Answer 2

Answer:

4√3 cm

Step-by-step explanation:

$Area \: of \: an \: equilateral \: triangle = \frac{ \sqrt{3} }{4} {a}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ \sqrt{3} }{4} \times {8}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ \sqrt{3} }{4} \times64 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 16 \sqrt{3} \: \: cm ^{2} \\ Area \: of \: triangle = \frac{1}{2} \times base \times altitude \\ 16 \sqrt{3} = \frac{1}{2} \times 8\times altitude \\ 16 \sqrt{3} =4 \times altitude \\ altitude = \frac{16 \sqrt{3}}{4} \\ altitude = 4 \sqrt{3} \: \: cm$