Question

find altitude of a Trapezium whose area is 65 CM square and whose bases are 13 cm and 26 CM​

Answer 1

Given :-

• Area of Trapezium = 65cm²
• First Parallel Side = 13cm
• Second Parallel Side = 26cm

To Find :-

• Height of the Trapezium

Solution :-

${:} \longrightarrow \sf{\sf{ Area \:of\: Trapezium\: =\: \dfrac{1}{2} \: \times \: Height \: \times \: Sum \: of \: Parallel \: Sides}}\\ \\ {:} \longrightarrow \sf{\sf{ 65\: =\: \dfrac{1}{2} \: \times \: Height \: \times \: ( \: 13 \: + \: 26 \: )}} \\ \\ {:} \longrightarrow \sf{\sf{ 65\: =\: \dfrac{1}{2} \: \times \: Height \: \times \: 39}} \\ \\ {:} \longrightarrow \sf{\sf{ 65\: \times \: 2 \: = \: Height \: \times \: 39}} \\ \\ {:} \longrightarrow \sf{\sf{ 130\: = \: Height \: \times \: 39}} \\ \\ {:} \longrightarrow \sf{\sf{ \dfrac{130}{39} \: = \: Height }} \\ \\ {:} \longrightarrow \sf \boxed{\bf{ 3.3cm \: \: = \: Height }}$

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Therefore, Height of the Trapezium is 3.3cm

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Answer 2

GIVEN :-

*Area of Trapezium = 65cm²

*First Parallel Side = 13cm

*Second Parallel Side = 26cm

Height of trapezium = ?

Area of Trapezium = 1/2 * Height * (sum of the parallel sides)

65 cm² = 1/2 * Height * (13+26)

65 = 1/2 * Height * 39

65 * 2 = Height * 39

130 = Height * 39

Height = 130/39

Height = 3.3 cm

HENCE, HEIGHT OF THE GIVEN TRAPEZIUM IS 3.3 CM.

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