Math, asked by jayeshtak711, 1 year ago

Find AM of two positive numbers whose GM and H. M. are 4 and 16/5 respectively.​

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Answers

Answered by Raghav1330
34

Answer:5 is the answer

Step-by-step explanation:

AM is arithmetic mean of numbers between two given no in ap sequence

GM is geometric mean similarly in GP

HM is harmonic mean similar way in HP

Let there be two numbers x and y.

Now am will be given by x+y/2

GM will be given by square root of xy

HM will be 2xy divided by x+y

Now AM * HM is x+y* 2xy* xy/ 2.x+y =(xy)²= GM²

GM= √(AM*HM)

4= √AM*4/√5

AM=5

Answered by alfiyap805
17

Answer:

AM=5

Step-by-step explanation:

GM=4,HM=16/5, AM=?.................given

We know:

(GM)^2=AM*HM

(4)^2=AM*16/5

16=AM*16/5

AM=16*5/16

AM=5

THE ANSWER IS 5.

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