Find AM of two positive numbers whose GM and H. M. are 4 and 16/5 respectively.
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Answered by
34
Answer:5 is the answer
Step-by-step explanation:
AM is arithmetic mean of numbers between two given no in ap sequence
GM is geometric mean similarly in GP
HM is harmonic mean similar way in HP
Let there be two numbers x and y.
Now am will be given by x+y/2
GM will be given by square root of xy
HM will be 2xy divided by x+y
Now AM * HM is x+y* 2xy* xy/ 2.x+y =(xy)²= GM²
GM= √(AM*HM)
4= √AM*4/√5
AM=5
Answered by
17
Answer:
AM=5
Step-by-step explanation:
GM=4,HM=16/5, AM=?.................given
We know:
(GM)^2=AM*HM
(4)^2=AM*16/5
16=AM*16/5
AM=16*5/16
AM=5
THE ANSWER IS 5.
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