Question

find amount and CI of P = 15000 Rate = 6% and time = 2 years compounded half yearly​

Answer 1

Answer:

Answer is attached here

Answer 2

Given :

Principle : ₹15000

Rate of interest : 6%

Time : 2 years

To find :

The amount and the compound interest.

Solution :

First, we'll find the amount.

$\sf \dashrightarrow Amount = Principle \bigg( 1 + \dfrac{Rate}{100} \bigg)^{T2}$

$\sf \dashrightarrow 10000 \bigg( 1 + \dfrac{6}{100} \bigg)^{2(2)}$

$\sf \dashrightarrow 10000 \bigg( 1 + \dfrac{3}{20} \bigg)^{4}$

$\sf \dashrightarrow 10000 \bigg( \dfrac{20 + 3}{20} \bigg)^{4}$

$\sf \dashrightarrow 10000 \bigg( \dfrac{23}{20} \bigg)^{4}$

$\sf \dashrightarrow 10000 \bigg( \dfrac{23^4}{20^4} \bigg)$

$\sf \dashrightarrow 10000 \bigg( \dfrac{279841}{160000} \bigg)$

$\sf \dashrightarrow \dfrac{10000 \times 279841}{160000} = \dfrac{2798410000}{160000}$

$\sf \dashrightarrow \cancel \dfrac{2798410000}{160000} = 17490.0625$

Now, we can find the compound interest.

Compound interest :

$\sf \dashrightarrow Amount - Principle$

$\sf \dashrightarrow 17490.0625 - 15000$

$\dashrightarrow$₹$\sf 2490.0625$

Hence, the amount and compound interest are ₹17490.0625 and ₹2490.0625 respectively.