Question

Find amount and compound interest if principal = Rs 15000, R = 10% p.a. and Time is 2 years.​

Answer 1

$\huge{\underline{\underline{\mathbb{\red{ Answer:-}}}}}$

Compound Interest = ₹3150

$\huge{\underline{\underline{\mathbb{\red{Question:-}}}}}$

Find amount and compound interest if principal = Rs 15000, R = 10% p.a. and Time is 2 years.

${\sf{\underline{\green{\sf{ Given}}}}}$

Principal (p) = ₹15000

Rate of Interest (r) = 10 % p.a

Time (t) = 2 years

Solution :-

For the first year

here ,

p = ₹ 15000

r = 10 %

t = 1 yrs

Therefore ,

$s.i = \frac{p \times r \times t}{100}$

$s.i = \frac{15000 \times 10 \times 1}{100}$

$s.i = 1500$

∴ Interest for the first year = ₹1500

So ,

⠀ Amount = p + s.i

⠀ ⠀ ⠀ ⠀ ⠀ = ₹ ( 15000 + 1500 )

⠀ ⠀ ⠀ ⠀⠀ = ₹ 16500

For second year

here ,

p = ₹16500

r = 10 %

t = 1 yrs

Therefore,

$s.i = \frac{p \times r \times t}{100}$

$s.i = \frac{16500 \times 10 \times 1}{100}$

$s.i = 1650$

So ,

Compound Interest for two years

= first S.I + second S.I

= ₹ ( 1500 + 1650 )

= ₹ 3150

${\sf{\underline{\boxed{\green{\sf{ hence, }}}}}}$

$\bold{\underline{\underline{\red{C.I\: => ₹3150}}}}$