Math, asked by simranjksandhu0910, 4 months ago

Find amount and compound interest on 31250
for 3 years at 8% per annum compounded
annually

Answers

Answered by MoodyCloud
64
  • Amount is 39366.
  • Compound interest is 8116.

Step-by-step explanation:

Given:-

  • Principal is 31250.
  • Time period is 3 years.
  • Rate of interest is 8%.

To find:-

  • Amount.
  • Compound interest.

Solution:-

  • Here, Interest is Compounded annually.

So,

 \boxed{\sf \bold{Amount = P \bigg(1 + \dfrac{r}{100} \bigg) ^{n} }}

Where,

  • P is principal.
  • r is rate of interest.
  • n is time period

So, Put the values in formula:

\sf \longrightarrow 31250  \times  \bigg(1 +  \dfrac{8}{100}  \bigg)^{3}  \\  \\

\sf \longrightarrow 31250 \times  \bigg( \dfrac{100 + 8}{100}  \bigg)^{3}  \\  \\

\sf \longrightarrow 31250  \times  \bigg( \dfrac{108}{100}  \bigg)^{3} \\ \\

\sf \longrightarrow 31250 \times  \dfrac{1259712}{1000000}  \\  \\

\sf \longrightarrow 31250  \times 1.259712 \\  \\

\longrightarrow   \blue{\boxed{ \sf \bold{ 39366}} \bigstar}  \\

Thus,

Amount is 39366.

Now,

 \boxed{\sf \bold{C.I = Amount - Principal }}

[C.I means Compound interest]

\sf \longrightarrow 39366 - 31250 \\  \\

\sf \longrightarrow  \purple{  \boxed{\bold{8116}}\star} \\

Therefore,

Compound interest is 8116.


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Answered by BrainlyHero420
62

Answer:

Given :-

  • Principal = Rs 31250
  • Rate of Interest = 8%
  • Time = 3 years

To Find :-

  • What is the amount and compound interest.

Formula Used :-

To find interest we know that,

\boxed{\bold{\large{A\: =\: P\bigg(1 + \dfrac{r}{100}\bigg)^{n}}}}

where,

  • A = Amount
  • P = Principal
  • r = Rate of Interest
  • n = Time

To find compound interest we know how,

\boxed{\bold{\large{C.I\: =\: A\: -\: P}}}

where,

  • C.I = Compound Interest
  • A = Amount
  • P = Principal

Solution :-

To find Amount,

Given :

  • P = Rs 31250
  • r% = 8%
  • n = 3 years

According to the question by using the formula we get,

A = 31250 \times \bigg(1 + \dfrac{8}{100}\bigg)^{3}

A = 31250 \times \bigg(1 + \dfrac{{\cancel{8}}}{\cancel{100}}\bigg)^{3}

A = 31250 \times \bigg(1 + \dfrac{4}{50}\bigg)^{3}

A = 31250 \times \bigg(\dfrac{54}{50}\bigg)^{3}

A = 31250 \times \dfrac{54}{50} \times \dfrac{54}{50} \times \dfrac{54}{50}

A = \dfrac{{\cancel{4920750000}}}{{\cancel{125000}}}

A = Rs 39366

\therefore The amount is Rs 39366 .

To find compound interest,

C.I = 39366 - 31250

C.I = Rs 8116

\therefore The compound interest is Rs 8116 .


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