Question

Find amount and compound interest on 31250
for 3 years at 8% per annum compounded
annually
​

Answer 1

Answer:

Here's your answer dear......

Step-by-step explanation:

Given:

Present value= ₹ 31250

Interest rate =8%per annum

Time=3 years

To find the amount we have the formula,

Amount (A)=P(1+(R/100)n

Where P is present value, r is rate of interest, n is time in years.

Now substituting the values in above formula we get,

A=31250(1+8/100)³

A=31250(1+2/25)³

A=31250(27/25)³

A = 31250 × 19683/15625 = 2 × 19683

A=Rs 39366

Compound interest=A-P

39366-31250=Rs-8166....

hope this will helpful to you....

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Answer 2

Given :-

Principal = Rs 31250

Rate of Interest = 8%

Time = 3 years

To Find :-

What is the amount and compound interest.

Formula Used :-

❶ To find interest we know that,

$\boxed{\bold{\large{A\: =\: P\bigg(1 + \dfrac{r}{100}\bigg)^{n}}}}$

where,

A = Amount

P = Principal

r = Rate of Interest

n = Time

❷ To find compound interest we know how,

$\boxed{\bold{\large{C.I\: =\: A\: -\: P}}}$

where,

C.I = Compound Interest

A = Amount

P = Principal

Solution :-

❶ To find Amount,

Given :

P = Rs 31250

r% = 8%

n = 3 years

According to the question by using the formula we get,

⇒ A = $31250 \times \bigg(1 + \dfrac{8}{100}\bigg)^{3}$

⇒ A = $31250 \times \bigg(1 + \dfrac{{\cancel{8}}}{\cancel{100}}\bigg)^{3}$

⇒ A = $31250 \times \bigg(1 + \dfrac{4}{50}\bigg)^{3}$

⇒ A = $31250 \times \bigg(\dfrac{54}{50}\bigg)^{3}$

⇒ A = $31250 \times \dfrac{54}{50} \times \dfrac{54}{50} \times \dfrac{54}{50}$

⇒ A = $\dfrac{{\cancel{4920750000}}}{{\cancel{125000}}}$

➠ A = Rs 39366

$\therefore$ The amount is Rs 39366 .

❷ To find compound interest,

↦ C.I = 39366 - 31250

➥ C.I = Rs 8116

$\therefore$ The compound interest is Rs 8116 .