find amount interest and compound amount for rs 1280 at 12/1/2% rate of interest in 2 year
Answers
Answer:
Answer:
compound interest = Rs 978
compound interest = Rs 978Amount (A) = Rs 13778
Step-by-step explanation:
We have,
Principal (P) = Rs 12800
Time (T) = 1 year
Rate of interest = 15/2 p.a
Rate of interest semi annually (r) = 1/2×(15/2)= 15/4 %
Number of times interest paid (n)= 2
/* we know that,
\boxed { Amount (A)=P\big(1+\frac{r}{100}\big)^{2}}
Amount(A)=P(1+
100
r
)
2
A = 12800\big(1+\frac{\frac{15}{4}}{100}\big)^{2}A=12800(1+
100
4
15
)
2
A = 12800\big(\frac{400+15}{400}\big)^{2}A=12800(
400
400+15
)
2
\implies A = 12800\big(\frac{415}{400}\big)^{2}⟹A=12800(
400
415
)
2
\implies A = 12800\times \frac{415\times 415}{400\times 400 }⟹A=12800×
400×400
415×415
\implies A = Rs\:13778⟹A=Rs13778
\begin{lgathered}Compound \: interest = A - P\\=Rs \:13778 - Rs\:12800\\=Rs\:978\end{lgathered}
Compoundinterest=A−P
=Rs13778−Rs12800
=Rs978
Therefore,
compound interest = Rs 978
Amount (A) = Rs 13778