Question

find amount of glucose and amount of water required to make 500g of 40 percent of soltion

Answer 1

Answer:

Correct option is

B

18 g

For urea M=0.2 

M=Mass of solventMoles of urea (n)×1000

Relative lowering of vapour pressure

=10000.2×18=10003.6                   

For glucose

Relative lowering in vapour pressure= 180×500Mass of glucose (W)×18

=5000W                               

From (1) & (2), 

10003.6=5000W

⇒W=18g