find amount of work done in blowing a soap bubble of surface tension 0.07 Newton per metre from radius 2 centimetre to 5 cm
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Answer:
369.6 J
Explanation:
T equals 0.07
r1 equals 2 cm equals 2/100
r2 equals 5 cm = 5/100
a1 = 4Π(2/100)^2
a2 = 4Π(5/100)^2
A equals (8Π×21)/100^2
Therefore, W = T ×A
= 0.07 × 8 × 22 × 3 × 10^-4
= 36.96 × 10^-4
= 369.6 × 10^-3
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