Question

find amount when fuincipal
is 50ooirate is 10% time is
9 5 yas applying simple intust?​

Answer 1

Correct Question:

Find the amount when the principal is Rs. 5000, the rate is 10 % and time is 9.5 years by applying the simple interest formula.

Given:

• Principal = Rs. 5000
• Rate = 10 %
• Time = 9.5 years

What To Find:

We have to find -

• Amount

Formula Needed:

$\bf \to \: SI = \dfrac{PRT}{100}$

$\bf \to \: A = P + SI$

Solution:

• Finding the SI.

Use the formula,

$\bf \to \: SI = \dfrac{PRT}{100}$

Substitute the values,

$\bf \to \: SI = \dfrac{5000 \times 10 \times 9.5}{100}$

Cancel the zeros,

$\bf \to \: SI = 50 \times 10 \times 9.5$

Multiply the values,

$\bf \to \: SI = Rs. \: 4750$

• Finding the Amount.

Use the formula,

$\bf \to \: A = P + SI$

Substitute the values,

$\bf \to \: A = 5000 + 4750$

Add the values,

$\bf \to \: A = Rs. \: 9750$

Final Answer:

∴ Thus, the amount is Rs. 9750.

Answer 2

Correct Question :

• Find the amount when the principal is Rs. 5000, the rate is 10 % and time is 9.5 years by applying the simple interest formula.

Given :

• Principal (P) = Rs. 5000
• Time (T) = 9.5 years
• Rate (R) = 10%

To Find :

• Amount

Solution :

Finding simple Interest

⟹ SI = P × R × T/100

⟹ SI = 5000 × 9.5 × 10/100

⟹ SI = 50000 × 9.5/100

⟹ SI = Rs. 4750

Now, Finding Amount

⟹ Amount = P + SI

⟹ Amount = 5000 + 4750

⟹ Amount = Rs. 9750

∴ Required Amount is Rs. 9750