Question

Find an

a.p. of 8 terms, whose first term is 1/2 and last term is17/6

Answer 1

a = 1/2, a+7d =17/6

$7d = \frac{17}{6} - \frac{1}{2} \\ 7d = \frac{14}{6} \\ d = \frac{1}{3}$
The AP is

$\frac{1}{2} . \: \frac{5}{6} .........$

Mark this answer as brainliest answer

Answer 2

Answer:

a=1by2

a+7d=17 by 6

7d=17by6-1by2

d=14/6×1/7

d=13

putting value of d

a2=1by2+1by3

we get 56

then putting value of a and d we get AP of first 8 terms