Question

find an A.P. whose 4th term is 9 and the sum of its 6th term and 13th term is 40

Answer 1

a4=9;a6+a13=40
a+3d=9
a=9-3d

a+5d+a+12d=40
put a value in above equation
9-3d+5d+9-3d+12d=40
18+11d=40
11d=22
d=2
a=9-3(2)
a=3

AP:a;a+d;a+2d.....
=3;3+2;3+2(2).....
=3;5;7....

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