Question

Find an angle such that the measure of its supplement is 10 degrees less than 3 times the measure of its
complement​

Answer 1

Answer

Let the angle be x

Complementary angle = 90 - x

Supplementary angle = 180 - x

According to the question,

$\implies\sf 3(90 - x) - 10 = 180 - x$

$\implies\sf 270 - 3x - 10 = 180 - x$

$\implies\sf 260 - 3x = 180 - x$

$\implies\sf 260 - 180 = 3x - x$

$\implies\sf 80 = 2x$

$\implies\sf x = 40\degree$

Verification :-

Complementary angle = 90 - 40 = 50

Supplementary angle = 180 - 40 = 140

According to the question :-

Supplementary angle is 10 less than thrice of complementary angle -

3 × 50 - 10 = 150 - 10 = 140

LHS = RHS

Hence verified

Answer 2

Answer:

Complementary angle = 90 - x

Supplementary angle = 180 - x

Step-by-step explanation:

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