Question

find an angle such that the measures of its supplement is 10degrees less than 3 times the mesures of its complement​

Answer 1

Answer:

let angle is x

it's supplement is 180-x

it's complement is 90-x

according to question,

180-x= 3(90-x) -10

180-x=270-3x-10

180-x=260-3x

2x=80

x= 40

Answer 2

Answer:

let the angle be x

complement =90-x

supplement=180-x

180-x=3(90-x)-10

180-x=270-3x-10

180-x=260-3x

4x=440

x=110