find an angle which is double of its supplement
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So that it remains two supplement that is measured by angle at 180 degree and then consider it as X x+2x=180°, 3x=180°, x=180÷3=60°, 2×60=120°. Therefore, two supplement angles takes place by 180 degree.
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So that it remains two supplement that is measured by angle at 180 degree and then consider it as X x+2x=180°, 3x=180°, x=180÷3=60°, 2×60=120°. Therefore, two supplement angles takes place by 180 degree.
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