find an angle which is two third of its complement
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0
Let the angle be x.
And its complement angle be y
By the problem x=
3
2
y
We know that,
Sum of complementary angles is 90
0
⇒y+
3
2
y=90
0
⇒
3
3y+2y
=90
0
⇒
3
5y
=90
0
⇒5y=90×3
y=
5
90×3
y=36
0
Therefore,
The angles are 54
0
,36
0
.
Answered by
28
Given :
- One of the angle is ⅔ of its complement.
To Find :
- The two complementary angles.
Solution :
✰ As we know that, Two angles whose sum is 90° are called complementary angles. Therefore :
⟹ Let the First angle be x
⟹ Let it's complement angel be y
⟹ By the Question : x = ⅔ y
⠀
According to the Question :
⟼ Sum of Complements = 90°
⟼ y + 2/3 y = 90°
⟼ 3y + 2y / 3 = 90°
⟼ 3y + 2y = 90 × 3
⟼ 3y + 2y = 270
⟼ 5y = 270
⟼ y = 270 / 5
⟼ y = 54°
Therefore :
- First angle = y = 54°
- Second angle = x = ⅔y = 2/3 × 54 = 2 × 18 = 36°
Hence the Two Complementary angles are 54° and 36°
________________
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