Find an ap whose first term is 9 and sum of 6 and 13th term is 40
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a=9,
a+12d+a+5d=40
9+17d+9=40
17d=40-18
17d =22
d=22/17
the required AP is
9,175/17,197/17
a+12d+a+5d=40
9+17d+9=40
17d=40-18
17d =22
d=22/17
the required AP is
9,175/17,197/17
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