Find an approximate value of (17)1/3 by using Bisection Method
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Let f the function defined by: ∀x∈R,f(x)=x3−25. We know that f(3
√
25
)=0 and the function has only one root since it's strictly increasing and continuous.
f(0) for example is negative and f(3) is positive so you can consider the interval [0,3]. You can take any other numbers.
The number of iterations is as you wish. As much it's bigger, the value you get is closer to 3
√
25
.
Step-by-step explanation:
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