Math, asked by Masterskull, 1 year ago

Find an arithmetic progression which lies between 200 and 300 and all are multiples of 7.

Answers

Answered by harshit1416
0
203.210.217............294
if u like my ans so pls give me brainliest
Answered by Anonymous
1
                                                          ☺☺☺

An A.P. that lies between 200 and 300 and all are multiples of 7.

203,210,217,224,231,238,245,252,259,266,273,280,287,294.

First term = 203

Last term = 294

Common difference = +7.

Number of terms = 14.

 •  How did we find first term ?

Since the A.P.'s term should be multiple of 7 .So, first term of A.P. will be first multiple of 7 between 200 and 300.
By dividing 200 by 7, 200/7 = 28.57..... So the first term will be 29 x 7 = 203.

 • How did we find last term ?

The last term of A.P. will be the greatest multiple of 7 between 200 and 300.
So, 300 / 7 = 42.18..... So the last term = 42 x 7 = 294.


                                          ☺☺☺



Anonymous: Thanks Bro
Similar questions