Find an equation for the line with the given properties
Express your answer using either the general form or the slope-intercept form of the equation of a line
X-intercept, 3
Y-intercept :-4
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The line has an x- intercept at x = -4 and y intercept at y= 5, this means that the line passes through the points (-4,0) and (0,5) Now we find the slope m of the line passing through the points (-4,0) and (0,5) (x-intercept).
The slope of the line is:
m= y2- y1 / X2 - X1 = 5-0/0-(-4) = 5/4
point- slope formula:
(y-y1) is the given point.
Now substituting the values:
y - 0 = 5/4 (x-(-4))
= y= 5/4 (x+4)
4y = 5(x+4)
4y = 5x + 20
4y - 20 = 5x
Hence, the equation of the line is 4y-20 = 5x.
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