Question

Find an equation for the plane perpendicular to the vector A=2i+3j+6k and passing through the terminal point of the vector B=i+5j+3k

Answer 1

Answer:

2(x − 1) + 3(y − 5) + 6(z − 3) = 0

Step-by-step explanation:

In general, The plane perpendicular to (a,b,c) and passing through (x0,y0,z0) is a (x−x0)+b (y−y0)+c (z−z0) = 0

Now as per given information, we see that

The equation can be found by observing that the plane passes through the point (1, 5, 3) with normal vector

2(x − 1) + 3(y − 5) + 6(z − 3) = 0