Question

Find an equation of the circle having the given center and radius. Center ​(-2​, 3​), radius, radical 3

Answer 1

Answer:

x2+y2−4x+6y+4=0.

Explanation:

The eqn. of a circle with centre (h,k) and radius r is given by,

(x−h)2+(y−k)2=r2.

Accordingly, the reqd. eqn. is,

(x−2)2+(y+3)2=32, i.e.,

x2+y2−4x+6y+4=0.

Answer 2

(x+2)^2+(y-3)^2=3^2
(x+2)^2+(y-3)^2=9