find an equation of the circle of radius a and lying in the second quadrant such that it is tangent to both the axes
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Answer:
x^2 + y^2 + 2ax - 2ay + a^2 = 0
Step-by-step explanation:
Using the property that tangents are perpendicular to radius
The axes and radius of circle perpendicular to them make a square of side 'a'
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