Question

Find an equation of the parabola in standard form passing through the points:
(-2, 9), (-4, 5), (1, 0)

So far I have
If y=ax^2+bx+c, then
4a-2b+c = 9
16a-4b+c = 5
a+b+c = 0

Now what?

Answer 1

Answer:

..........10 11 01 01 001

001

Step-by-step explanation:

0010 001

Answer 2

Answer:

Solve it you have three equation and three variables a, b and c after getting the value of a, b and c put it in y = ax^2+bx+c you will get the answer