Find an equation of the parabola in standard form passing through the points of (-2, 9), (-4, 5), (1, 0).
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Answer:
which one exercise it is...........
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Step-by-step explanation:
2 possibilities for a standard parabola, vertical or horizontal
either it's of the form y=ax²+ bx + c, a downward opening parabola with a<0
or it's x = ay² + bx + c with a>0
either one collapses to y = a(x-h)²+ k
or to x = a(y-k) + h
plug in the 3 points separately to get a series of equations
Either you get one parabola, two parabolas possible, or none.
If none there still could be non-vertical, non-horizontal parabolas, but they would have an xy term, which is quadratic, but not the usual x² or y²
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