Question

Find an expression for the magnetic field induction at the centre of the coil bent in the form of a square of side 2a and carrying current I.​

Answer 1

Explanation:

square is bent the form of coil .......

the perimeter of square is = 8a

which is equal with perimeter of the coil .

so 2πr = 8a { r = radius of coil }

r = 4a/ π ..

Magnetic field induction at the centre of the coil = (Mu not /2 ) × (I / r ) { r is radius & munot = 4π× 10^-7 }

= (10^-7 × I × π ×π ) / 2a