Find an expression for the magnetic field induction at the centre of the coil bent in the form of a square of side 2a and carrying current I.
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Explanation:
square is bent the form of coil .......
the perimeter of square is = 8a
which is equal with perimeter of the coil .
so 2πr = 8a { r = radius of coil }
r = 4a/ π ..
Magnetic field induction at the centre of the coil = (Mu not /2 ) × (I / r ) { r is radius & munot = 4π× 10^-7 }
= (10^-7 × I × π ×π ) / 2a
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