Question

find an expression for the volume of liquid per second through a pipe when the flow is steady assuming it depends on the radius of the pipe

Answer 1

Answer:

let me explain

Explanation:

let us consider a pipe of length l and radius r is concted to a motor which is passing liquid with a speed of y meter per second

Now we know that pipe contains some volume which can be written

pi R^2h

it means it is that volume(i.e volume of liquid)

which pipe can hold. but the liquid is in motion with speed of y ms^-1

so the total lqiud must be

volume of pipe × speed of liquid

pi r^2h× y

hope it helps you. thanks