Question

Find an integer a such that (a+6=0) (5+a=0) (-8+a=0)​

Answer 1

Answer:

In ( a + 6 = 0 ) a = -6

( 5 + a = 0 ) a = -5

( -8 + a = 0 ) a = 8

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Answer 2

Answer:

Step-by-step explanation:

a + 6 = 0

- 6 + 6 = 0

So a= - 6 is the answer.

5 + a = 0

5 + ( - 5 )= 0

5 - 5 = 0 (since + × - = - )

So a = - 5 is the answer.

- 8 + a = 0

- 8 + 8 = 0

So a = 8 is the answer.