Question

Find an integral by inspection method -

sin 2x - 4e^3x

Answer 1

Answer:

Hey mate.

See the attachment for the solution.

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Answer 2

Step-by-step explanation:

ANSWER

We know that,

dx

d

(−

2

1

cos2x−

3

4

e

3x

)=sin2x−4e

3x

Therefore, the anti derivative of (sin2x−4e

3x

) is (−

2

1

cos2x−

3

4

e

3x

).