Find an. Sn =169 and Ap:1,3,5,7...
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vaibhavpick466:
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Answered by
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Hi mate
Here is ur answer ⬇️⬇️⬇️
Ap : 1,3,5,7....
d=3-1=2
a=1
➡️sn=n/2[2a+(n-1)d]
169=n/2[2(1)+(n-1)2]
338=n[2+2n-2]
338=n(2n)
338/2n=n
169/n=n
n^2=169
➡️n=13
an=a+(n-1)d
=1+(13-1)2
=1+(12)2
=1+24
➡️an=25
I hope this will help you
⚛️mark as brainliest ⚛️
Here is ur answer ⬇️⬇️⬇️
Ap : 1,3,5,7....
d=3-1=2
a=1
➡️sn=n/2[2a+(n-1)d]
169=n/2[2(1)+(n-1)2]
338=n[2+2n-2]
338=n(2n)
338/2n=n
169/n=n
n^2=169
➡️n=13
an=a+(n-1)d
=1+(13-1)2
=1+(12)2
=1+24
➡️an=25
I hope this will help you
⚛️mark as brainliest ⚛️
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